Problem. Pay Rs. 10,000 at t=0; receive Rs. 3,500 at t=1, Rs. 4,000 at t=2, Rs. 4,500 at t=3. Write the equation of value at t=0 for unknown rate i.
Solution.
10,000=1+i3,500+(1+iSolving for i (trial and improvement, or calculator) gives the internal rate of return — the rate that makes the equation hold.
Trial at i=5% (left-hand side = PV of receipts):
1.053,500+(1.05)24,000NPV ≈10,848−10,000=+848 — rate is too low (receipts are worth more than cost).
Trial at i=10%:
1.103,500+(1.10)24,000NPV ≈−131 — rate is too high. The IRR lies between 5% and 10%; further trials (or a calculator) give i≈9.2% to one decimal.